x^2+11x-432=0

Solution for x^2+11x-432=0 equation:

x^2+11x-432=0

a = 1; b = 11; c = -432;
Δ = b2-4ac
Δ = 112-4·1·(-432)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-43}{2*1}=\frac{-54}{2}
=-27
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+43}{2*1}=\frac{32}{2}
=16
$